# How do you find the volume of the region bounded by y = (x)^(1/2); y=0 and x = 4 rotated about the x-axis?

$8 \pi$
$y = {x}^{\frac{1}{2}}$
$V = \pi {\int}_{0}^{4} {y}^{2} \mathrm{dx} = \frac{\pi}{2} {\left[{x}^{2}\right]}_{0}^{4} = 8 \pi$