How do you find the volume of the solid bounded by x=y^2 and the line x=4 rotated about the x axis?

$8 \pi$
$x = {y}^{2}$
$V = \pi {\int}_{0}^{4} {y}^{2} \mathrm{dx} = \frac{\pi}{2} {\left[{x}^{2}\right]}_{0}^{4} = 8 \pi$