How do you find the x and y intercept and slope of #Y=1/2x+6#?

1 Answer
Jul 10, 2015

Answer:

The #y#-intercept is at (#0,6#), and the #x#-intercept is at (#-12,0#).

Explanation:

The "slope-intercept" form of a straight line equation is

#y = mx + b#,

where #m# is the slope and #b# is the #y#-intercept.

Your equation is

#Y = 1/2x +6#

If we compare the two equations, we see that #b = 6#.

So the #y#-intercept is at (#0,6#).

To get the #x#-intercept, we set #Y = 0# and solve for #x#.

#Y = 1/2x + 6#

#0 = 1/2x + 6#

#0 = x + 12#

#x = -12#

The #x#-intercept is at (#-12,0#).

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