How do you find the x and y-intercept given $2 y - 8 x = 7$ $2y-8x = 7$ ?

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Answer 1 · 2015-07-26T21:10:30

2y - 8x = 7. Find x and y intercepts.

To find y-intercept make x = 0 --> $y = \frac{7}{2}$ $y = 7/2$
To find x-intercept, make y = 0 --> $x = - \frac{7}{8}$ $x = -7/8$

How do you find the x and y-intercept given 2y-8x = 72y−8x=72y-8x = 7?