# How do you find the x and y-intercept given y=2/3x+12?

Jul 11, 2015

To find the intercept with the $x$ axis, let $y = 0$ and solve to get $x = - 18$

To find the intercept with the $y$ axis, let $x = 0$ and see that $y = 12$

#### Explanation:

When $y = 0$ we have:

$\frac{2}{3} x + 12 = 0$

Subtract $12$ from both sides to get:

$\frac{2}{3} x = - 12$

Multiply both sides by $\frac{3}{2}$ to get:

$x = - 12 \cdot \frac{3}{2} = - \frac{36}{2} = - 18$

So the intercept with the $x$ axis is at $\left(- 18 , 0\right)$

When $x = 0$ we have:

$y = \frac{2}{3} \cdot 0 + 12 = 0 + 12 = 12$

So the intercept with the $y$ axis is at $\left(0 , 12\right)$