How do you find the x and y intercept of #5x - 7y = 1#?

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Answer 1 · 2017-06-20T03:33:50

#x#-intercept: #(1/5, 0); " "y#-intercept: #(0, -1/7)#

Given: #5x - 7y = 1#

To find the #x#-intercept, set #y = 0# and solve for #x#:

#5x - 7(0) = 1#

#5x = 1#

#(5x)/5 = 1/5#
#x#-intercept: #(1/5, 0)#

To find the #y#-intercept, set #x = 0# and solve for #y#:

#5(0) - 7y = 1#

#-7y = 1#

#(-7y)/-7 = 1/(-7)#

#y#-intercept: #(0, -1/7)#