# How do you find the x and y intercept of 8y = 3x - 9?

Jun 9, 2017

See a solution process below:

#### Explanation:

To find the $x$-intercept, substitute $0$ for $y$ and solve for $x$:

$8 y = 3 x - 9$ becomes:

$8 \cdot 0 = 3 x - 9$

$0 = 3 x - 9$

$0 + \textcolor{red}{9} = 3 x - 9 + \textcolor{red}{9}$

$9 = 3 x - 0$

$9 = 3 x$

$\frac{9}{\textcolor{red}{3}} = \frac{3 x}{\textcolor{red}{3}}$

$3 = \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} x}{\cancel{\textcolor{red}{3}}}$

$3 = x$

$x = 3$

The $x$-intercept is $3$ or $\left(3 , 0\right)$

To find the $y$-intercept, substitute $0$ for $x$ and solve for $y$:

$8 y = 3 x - 9$ becomes:

$8 y = \left(3 \cdot 0\right) - 9$

$8 y = 0 - 9$

$8 y = - 9$

$\frac{8 y}{\textcolor{red}{8}} = - \frac{9}{\textcolor{red}{8}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{8}}} y}{\cancel{\textcolor{red}{8}}} = - \frac{9}{8}$

$y = - \frac{9}{8}$

The $y$-intercept is $- \frac{9}{8}$ or $\left(0 , - \frac{9}{8}\right)$