# How do you find the x and y intercepts for 2x - 2y + 5 = 0?

Jun 12, 2018

Intercepts such that: $\left(- \setminus \frac{5}{2} , 0\right)$ and $\left(0 , \setminus \frac{5}{2}\right)$

#### Explanation:

The y intercept will occur when $x = 0$, therefore by subbing in $x = 0$, we isolate y, to form the equation:

$- 2 y + 5 = 0$ which we solve to find $y = \setminus \frac{5}{2}$

The x intercept occurs when $y = 0$ therefore do the same procedure to get:

$2 x + 5 = 0$ which we solve to find $x = - \setminus \frac{5}{2}$

Jun 12, 2018

$\text{x-intercept "=-5/2,"y-intercept } = \frac{5}{2}$

#### Explanation:

$\text{to find the intercepts, that is where the graph crosses}$
$\text{the x and y axes}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$x = 0 \Rightarrow - 2 y = - 5 \Rightarrow y = \frac{5}{2} \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow 2 x = - 5 \Rightarrow x = - \frac{5}{2} \leftarrow \textcolor{red}{\text{x-intercept}}$