How do you find the x and y intercepts for #2x+y= -3#?

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Answer 1 · 2016-03-03T01:40:29

The x-intercept is #(-3/2,0)#.

The y-intercept is #(0,-3)#.

The x-Intercept is the value of #x# when #y=0#, and the y-intercept is the value of #y# when #x=0#.

X-Intercept

#2x+y=-3#

Set #y=0# and solve for #x#.

#2x+0=-3#

Simplify.

#2x=-3#

Divide both sides by #2#.

#x=-3/2#

The x-intercept is #(-3/2,0)#.

Y-Intercept

#2x+y=-3#

Set #x=0#.

#2(0)+y=-3#

Simplify.

#y=-3#

The y-intercept is #(0,-3)#.

graph{2x+y=-3 [-9.81, 10.19, -6.76, 3.24]}