# How do you find the x and y intercepts for 3x -4y =12?

Aug 8, 2018

$x$-intercept is $\left(4 , 0\right)$
$y$-intercept is $\left(0 , - 3\right)$

#### Explanation:

To find $x$ intercepts, make $y = 0$ since we know $x$ intercepts always have $0$ for the $y$ value of the coordinate
$3 x - 4 \left(0\right) = 12$
$x = 4$

So the $x$-intercept is $\left(4 , 0\right)$

To find $y$ intercepts, make $x = 0$ since we know $y$ intercepts always have $0$ for the $x$ value of the coordinate
$3 \left(0\right) - 4 y = 12$
$y = - 3$

So the $y$-intercept is $\left(0 , - 3\right)$