How do you find the x and y intercepts for #3x -4y =12#?

1 Answer
Aug 8, 2018

Answer:

#x#-intercept is #(4,0)#
#y#-intercept is #(0,-3)#

Explanation:

To find #x# intercepts, make #y=0# since we know #x# intercepts always have #0# for the #y# value of the coordinate
#3x-4(0)=12#
#x=4#

So the #x#-intercept is #(4,0)#

To find #y# intercepts, make #x=0# since we know #y# intercepts always have #0# for the #x# value of the coordinate
#3(0)-4y=12#
#y=-3#

So the #y#-intercept is #(0,-3)#