How do you find the x and y intercepts for #f(x)=-x^2+7x+18#?

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Answer 1 · 2018-05-21T17:58:43

y-intercept: #y = 18#

x-intercepts: #x=9, x=-2#

in the form #ax^2+bx +c# the y-intercept is #c# so in your function:

#f(x)=-x^2+7x+18#

#"y-int" = 18#

to find the x-intercept(s) if there are any, we need to factor and find our roots or solutions:

#-x^2+7x+18 =0#
#-(x + 2) (x - 9)=0#

#x=9, x=-2#