# How do you find the x and y intercepts for x-2y=4?

Nov 13, 2016

Intercepts are $\left(0 , - 2\right)$ and $\left(4 , 0\right)$

#### Explanation:

Given:

$x - 2 y = 4$

The intercept with the $x$ axis can be found by setting $y = 0$ - effectively "covering up" the $- 2 y$ term - to get:

$x = 4$

hence the $x$ intercept is at $\left(4 , 0\right)$

The intercept with the $y$ axis can be found by setting $x = 0$ or covering up the $x$ term to get:

$- 2 y = 4$

Then dividing both sides by $- 2$ we find:

$y = - 2$

So the $y$ intercept is at $\left(0 , - 2\right)$

graph{(x-2y-4)((x-4)^2+y^2-0.01)(x^2+(y+2)^2-0.01) = 0 [-8.29, 11.71, -5.08, 4.92]}