# How do you find the x and y intercepts for y = 2x + 18?

Nov 14, 2015

The plot crosses the y-axis when x=0 and it crosses the x-axis when y=0. So by substitution of 0 for one you find the value of the other by manipulation of the equation

#### Explanation:

If you meant to ask more than just how:

When $x = 0$
$y = \left(2 \times 0\right) + 18$

so the y-axis intercept is at $\left(x , y\right) \to \left(0 , 18\right)$
For a strait line graph it is always at the value of the constant.

So at the x-axis intercept $y = 0$

$0 = 2 x + 18$
$2 x = - 18$
$x = \frac{- 18}{2} = - 9$

So the x-axis intercept is at $\left(x , y\right) \to \left(- 9 , 0\right)$