# How do you find the x and y intercepts for y= 2x^2+3x - 5?

Jun 17, 2016

$x$ intercept $x = - \frac{5}{2} \mathmr{and} x = 1$
$y$ intercept $y = - 5$

#### Explanation:

To find $y$ intercept lying on y_axis so set $x = 0$ in the given equation :

Thus ,
$y = 2 {\left(0\right)}^{2} + 3 \left(0\right) - 5$
Hence,$y = - 5$

To find $x$ intercept we have to set $y = 0$ and solve the equation to find $x$

$2 {x}^{2} + 3 x - 5 = 0$
$= \left(2 x + 5\right) \left(x - 1\right)$

$2 x + 5 = 0$
$2 x = - 5$
$x = - \frac{5}{2}$

or $x - 1 = 0$
$x = 1$