Question

How do you find the x and y intercepts for `y= 2x^2+3x - 5`?

Answer 1

`x` intercept `x=-5/2 or x=1`
`y` intercept `y=-5`

Explanation:

To find `y` intercept lying on y_axis so set `x=0` in the given equation :

Thus ,
`y=2(0)^2+3(0)-5`
Hence,`y=-5`

To find `x` intercept we have to set `y=0` and solve the equation to find `x`

`2x^2+3x-5=0`
`=(2x+5)(x-1)`

`2x+5=0`
`2x=-5`
`x=-5/2`

or `x-1=0`
`x=1`