How do you find the x and y intercepts for #y=3x-2#?

2 Answers

Answer:

#y = -2#
#x = 0#
#(0,-2)#

Explanation:

Add two to both sides.
#y = 3x - 2#
to
#y + 2 = 3x#

Next, instead of #x#, put #y + 2#.
#y + 2= 3(y+2)#

Then, multiply #3# by #y# and #3# by #2#.
#y +2= 3y + 6#

Subtract #y# from both sides.
#2 + y = 3y + 6#
to
#2 = 2y + 6#

Subtract #6# from both sides.
#2 = 2y + 6#
to
#-4 = 2y#

Divide both sides by #2#.
#-4 = 2y#
to
#-2 = y#
Go back to the original equation. Replace #y# with #-2#.
#y = 3x - 2#
to
#-2 = 3x - 2#

Add #2# to both sides.
#-2 = 3x - 2#
to
#0 = 3x#

Divide both sides by #3#.
#0 = 3x#
to
#0 = x#

Hope that helped! : )

Apr 12, 2018

Answer:

The x-intercept is #(2/3,0)#.

The y-intercept is #(0,-2)#.

Explanation:

Given:

#y=3x-2#

X-intercept: value of #x# when #y=0#.

Substitute #0# for #y#.

#0=3x-2#

Add #2# to both sides.

#2=3x#

Divide both sides by #3#.

#2/3=x#

The x-intercept is #(2/3,0)#.

Y-intercept: value of #y# when #x=0#

#y=3x-2# is the slope-intercept form for a linear equation:

#y=mx+b#,

where:

#m# is the slope, and #b# is the y-intercept.

Therefore, the y-intercept is #(0,-2)#.

You can also substitute #2# for #x# and solve for #y#.

#y=3(0)-2#

#y=-2#

The y-intercept is #(0,-2)#.

graph{y=3x-2 [-10, 10, -5, 5]}