Question

How do you find the x and y intercepts for `y = (x+1)^2`?

Answer 1

y intercept at: `(0,1)`

`x` intercept at: `(-1,0)`

Explanation:

Looking at the graph, we can see that the curve intersects the `bby` axis where `bb(x=0)`, and the curve intersects the `bbx` axis where `bb(y=0)` Using this:

`y` intercept:

`y=(0+1)^2=1`

y intercept at: `(0,1)`

`x` intecept:

`(x+1)^2=0`

Taking roots of both sides:

`x+1=0`

`x=-1`

`x` intercept at `(-1,0)`

graph{y=(x+1)^2 [-5, 5, -1, 6.33]}