# How do you find the x and y intercepts for y = (x+1)^2?

May 8, 2018

y intercept at: $\left(0 , 1\right)$

$x$ intercept at: $\left(- 1 , 0\right)$

#### Explanation:

Looking at the graph, we can see that the curve intersects the $\boldsymbol{y}$ axis where $\boldsymbol{x = 0}$, and the curve intersects the $\boldsymbol{x}$ axis where $\boldsymbol{y = 0}$ Using this:

$y$ intercept:

$y = {\left(0 + 1\right)}^{2} = 1$

y intercept at: $\left(0 , 1\right)$

$x$ intecept:

${\left(x + 1\right)}^{2} = 0$

Taking roots of both sides:

$x + 1 = 0$

$x = - 1$

$x$ intercept at $\left(- 1 , 0\right)$

graph{y=(x+1)^2 [-5, 5, -1, 6.33]}