# How do you find the x and y intercepts for y=x^2 + 4x + 4?

Dec 21, 2015

$x$-intercept @ $x = - 2$
$y$-intercept @ $y = 4$

#### Explanation:

Original Equation:
$y = {x}^{2} + 4 x + 4$

$x$-intercept
Factor:
$y = \left(x + 2\right) \left(x + 2\right)$

Solve:
$x = - 2$

$x$-intercept @ $x = - 2$

$y$-intercept
Set $x$ equal to zero and solve:
$y = {\left(0\right)}^{2} + 4 \left(0\right) + 4$
$y = 0 + 4$
$y = 4$

$y$-intercept @ $y = 4$