# How do you find the x and y intercepts for y=x^2+6x-5?

Mar 14, 2016

x-intercept --> $- 3 \pm \sqrt{14}$

#### Explanation:

To find y-intercept, make x = 0 --> y = -5
To find x-intercepts, make y = 0 and solve the quadratic equation:
$y = {x}^{2} + 6 x - 5 = 0.$
$D = {d}^{2} = {b}^{2} - 4 a c = 36 + 20 = 56 = 4 \cdot 14$ --> $d = \pm 2 \sqrt{14}$
$x = - \frac{6}{2} \pm \frac{2 \sqrt{14}}{2} = - 3 \pm \sqrt{14}$

NOTE
$D = {d}^{2} = {b}^{2} - 4 a c$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a}$
$x = - \frac{b}{2 a} \pm \frac{\sqrt{{b}^{2} - 4 a c}}{2 a}$