How do you find the x and y intercepts of #8y=-2x+20#?

1 Answer
Jul 7, 2017

Answer:

#x#-intercept: #(10,0)#
#y#-intercept: #(0,5/2)#

Explanation:

First, isolate the #y# variable by dividing #8# on both sides.
#y=-2/8x+20/8#
#y=-1/4x+5/2#

To find the #x#-intercept, substitute #0# in for #y# and solve for #x#.
#0=-1/4x+5/2#
#-5/2=-1/4x# ---> multiply by the reciprocal, #-4#, on both sides
#x=20/2=10#

To find the #y#-intercept, substitute #0# in for #x# and solve for #y#.
#y=-1/4(0)+5/2#
#y=0+5/2=5/2#

Finally, write the intercepts as coordinates on a graph.
#x#-intercept: #(10,0)#
#y#-intercept: #(0,5/2)#

I hope this helps a lot! :)