# How do you find the x and y intercepts of 8y=-2x+20?

Jul 7, 2017

$x$-intercept: $\left(10 , 0\right)$
$y$-intercept: $\left(0 , \frac{5}{2}\right)$

#### Explanation:

First, isolate the $y$ variable by dividing $8$ on both sides.
$y = - \frac{2}{8} x + \frac{20}{8}$
$y = - \frac{1}{4} x + \frac{5}{2}$

To find the $x$-intercept, substitute $0$ in for $y$ and solve for $x$.
$0 = - \frac{1}{4} x + \frac{5}{2}$
$- \frac{5}{2} = - \frac{1}{4} x$ ---> multiply by the reciprocal, $- 4$, on both sides
$x = \frac{20}{2} = 10$

To find the $y$-intercept, substitute $0$ in for $x$ and solve for $y$.
$y = - \frac{1}{4} \left(0\right) + \frac{5}{2}$
$y = 0 + \frac{5}{2} = \frac{5}{2}$

Finally, write the intercepts as coordinates on a graph.
$x$-intercept: $\left(10 , 0\right)$
$y$-intercept: $\left(0 , \frac{5}{2}\right)$

I hope this helps a lot! :)