How do you find the x and y intercepts of #y=4x-2#?

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Answer 1 · 2017-01-31T01:41:47

See the entire explanation below:

Because this equation is in the slope-intercept form you can obtain the y-intercept directly from the equation.

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

or in this case:

#y = color(red)(4)x - color(blue)(2)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Therefore the y-intercept is #-2# or #(0, -2)#

To find the x-intercept we set #y# equal to #0# and solve for #x#:

#0 = 4x - 2#

#0 + 2 = 4x - 2 + 2#

#2 = 4x - 0#

#2 = 4x#

#2/4 = (4x)/4#

#1/2 = (cancel(4)x)/cancel(4)#

#1/2 = x# or #x = 1/2#

Therefore the x-intercept is #1/2# or #(1/2, 0)#