Question

How do you find the x intercept and y intercept for `y=x^2-x-2`?

Answer 1

To find the x-intercepts let y=0; `0=x^2-x-2 = (x-2)(x+1) -> x =12 or x = -1`
To find the y intercept let x = 0;
`y=0-0-2=-2`

Explanation:

To find x intercept let y = 0 and solve for x and to find the y-intercept let x=0 and solve for y