# How do you find the x intercept and y intercept for  y=x^2-x-2?

To find the x-intercepts let y=0; $0 = {x}^{2} - x - 2 = \left(x - 2\right) \left(x + 1\right) \to x = 12 \mathmr{and} x = - 1$
$y = 0 - 0 - 2 = - 2$