# How do you find the x intercepts for 3x^2 - 4x - 8 = 0?

Solve: $y = 3 {x}^{2} - 4 x - 8 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 16 + 96 = 112$ -> $d = \pm 4 \sqrt{7}$
$x = \frac{8}{6} \pm \frac{4 \sqrt{7}}{6} = \frac{4}{3} \pm \frac{2 \sqrt{7}}{3}$