# How do you find the x-value of the vertex of a parabola that has x-intercepts of -4 and 12?

Mar 25, 2016

The vertex V of the parabola is $\left(4 , - 64\right)$.

#### Explanation:

The parabolas that makes x-intercepts $- 4$ and 12 is
$y = \left(x + 4\right) \left(x - 12\right)$.

This can be rearranged as $y + 64 = {\left(x - 4\right)}^{2}$

The vertex is $\left(4 , - 64\right)$