Question

How do you find the x-value of the vertex of a parabola that has x-intercepts of -4 and 12?

Answer 1

The vertex V of the parabola is `( 4, -64 )`.

Explanation:

The parabolas that makes x-intercepts `-4` and 12 is
`y = ( x + 4 )( x - 12 )`.

This can be rearranged as `y + 64 = ( x - 4 )^2`

The vertex is `(4, -64)`