How do you find the y-intercept of #y = x^2 - 4x + 4#?

1 Answer
Dec 16, 2015

y-intercept#=#4

Explanation:

Since any y-intercept has an x-coordinate of #0#, substitute #0# as your #x# value into the equation and solve for #y#:

#y=x^2-4x+4#
#y=(0)^2-4(0)+4#
#y=0-0+4#
#y=4#

A quicker approach would be to look at the #c# value of the equation, which is also the y-intercept. Recall that the standard form of a quadratic equation is written like:

#y=ax^2+bx+c#

Thus, by looking at the equation, you can tell that the y-intercept is #4#.