Question

How do you find the zeroes for `y=x^2+3x+2`?

Answer 1

You may first want to factorise the equation.

Explanation:

You may notice that `2=1*2` and `3=1+2`
This leads to:
`y=x^2+3x+2=(x+1)*(x+2)`
For `y=0` either one of the factors need to be `=0`

This leads to `x=-1orx=-2`