Question

How do you find the zeroes of `f(x) =(x+5) (x^2-4)`?

Answer 1

`x=-5,-2,2`

Explanation:

`f(x)=0`
ie `(x+5)(x^2-4)=0`

`(x+5)(x-2)(x+2)=0`

So `x=-5,-2,2`