# How do you find the zeroes of f (x) =x^6 − 64?

Jul 2, 2015

First note that $64 = {2}^{6}$
Since the exponent is even, $64 = {\left(- 2\right)}^{6}$ also
You can now say that ${x}^{6} = {2}^{6} \mathmr{and} {x}^{6} = {\left(- 2\right)}^{6}$
In other words: $x = 2 \mathmr{and} x = - 2$