# How do you find the zeros, if any, of #y=x^2-3x+1# using the quadratic formula?

##### 1 Answer

May 6, 2018

#### Answer:

The solutions are

#### Explanation:

Given a quadratic equation

the quadratic formula states that the solutions, if any, are

The quantity **Determinant**, and you can tell the number of solutions by its sign:

- If
#Delta>0# , then the square root is well defined and not null, so you have two solutions. - If
#Delta=0# , the square root is zero as well. So, adding or subtracting it makes no difference, and you have two coincident solutions. - If
#Delta < 0# , the square root is not defined, and you have no solutions (at least using real numbers).

In your case,