How do you find the zeros, if any, of y= -x^4 -3x^2+17 using the quadratic formula?

Feb 18, 2016

$\pm \sqrt{\frac{- 3 + \sqrt{77}}{2}}$

Explanation:

if $a = {x}^{2}$ you will obtain:

$- {a}^{2} - 3 a + 17$

Apply the second degree formula:

$\frac{3 \pm \sqrt{{3}^{2} - 4 \times \left(- 1\right) \times 17}}{2 \times \left(- 1\right)}$

$\frac{3 \pm \sqrt{9 + 68}}{- 2}$

$\frac{3 \pm \sqrt{77}}{- 2}$

$\frac{- 3 \pm \sqrt{77}}{2}$

We know that $x = \sqrt{a}$

So the real solutions will be:

$\pm \sqrt{\frac{- 3 + \sqrt{77}}{2}}$