# How do you find the zeros of # y = -3x^2 + 4x -12 # using the quadratic formula?

##### 1 Answer

Mar 14, 2016

No real roots.

#### Explanation:

y = -3x^2 + 4x - 12 = 0

D = d^2 = b^2 - 4ac = 16 - 144 = - 128.

Since D < 0. there are no no real roots. Since a < 0, the parabola opens downward and it is completely below the x-axis.