# How do you find the zeros of  y = -3x^2 + 4x -12  using the quadratic formula?

Mar 14, 2016

No real roots.

#### Explanation:

y = -3x^2 + 4x - 12 = 0
D = d^2 = b^2 - 4ac = 16 - 144 = - 128.
Since D < 0. there are no no real roots. Since a < 0, the parabola opens downward and it is completely below the x-axis.