How do you find the zeros of # y = -3x^2 + 4x -12 # using the quadratic formula?
1 Answer
Mar 14, 2016
No real roots.
Explanation:
y = -3x^2 + 4x - 12 = 0
D = d^2 = b^2 - 4ac = 16 - 144 = - 128.
Since D < 0. there are no no real roots. Since a < 0, the parabola opens downward and it is completely below the x-axis.
