Question

How do you find the zeros of `y = -3x^2 - 5x + 23` using the quadratic formula?

Answer 1

`x= (-5+-sqrt301)/6`

Explanation:

To find the zeros, put y=0 and apply the quadratic formula.

Accordingly, `-3x^2 -5x +23=0`,

Or,`3x^2 +5x -23=0`

`x=(-5+-sqrt (5^2 -4*3*-23))/(2*3)`
`x= (-5+-sqrt301)/6`

                                                       **************