# How do you find the zeros of  y = -3x^2 - 5x + 23  using the quadratic formula?

Nov 26, 2015

$x = \frac{- 5 \pm \sqrt{301}}{6}$

#### Explanation:

To find the zeros, put y=0 and apply the quadratic formula.

Accordingly, $- 3 {x}^{2} - 5 x + 23 = 0$,

Or,$3 {x}^{2} + 5 x - 23 = 0$

$x = \frac{- 5 \pm \sqrt{{5}^{2} - 4 \cdot 3 \cdot - 23}}{2 \cdot 3}$
$x = \frac{- 5 \pm \sqrt{301}}{6}$

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