How do you find the zeros of #y=4x^2+1#?
There are no zeroes.
You can use the discriminant,
The equation is already in the right form of
In this situation, a = 4, b = 0, and c = 1.
When you use the discriminant, if the answer is creater than zero, there are two roots (aka zeroes); if the answer is zero, there is one root; and if the answer is smaller than zero, there are no roots.
Since the answer is -16, there are no zeroes.