How do you find the zeros of #y=4x^2+1#?

1 Answer
May 21, 2017

There are no zeroes.


You can use the discriminant, #b^2-4ac# .
The equation is already in the right form of #y = ax^2+bx+c# .
In this situation, a = 4, b = 0, and c = 1.
When you use the discriminant, if the answer is creater than zero, there are two roots (aka zeroes); if the answer is zero, there is one root; and if the answer is smaller than zero, there are no roots.
Since the answer is -16, there are no zeroes.