How do you find the zeros of # y = -9/2x^2 + 3/2x – 3/2 # using the quadratic formula?
The solutions of this equation are imaginary.
The roots of this equation are:
The zeroes (solutions) occur when
Standard form for a quadratic equation is
The quadratic formula is
Substituting in the values of
Since the total under the square root sign yields a negative number, there are no real roots of the equation, only imaginary roots.
That means the roots of this equation are: