Question

How do you find the zeros, real and imaginary, of `=5(x-3)^2+3` using the quadratic formula?

Answer 1

`x=3+-isqrt(3/5)`

Explanation:

For using quadratic formula, the given expression has to be put in quadratic form , that is `5x^2 -30x +48=0`. Comparing with the quadratic formula a= 5, b= -30 and c= 48. Expression `b^2-4ac<0` hence the equation would have imaginary roots. The roots would be `x=3+-isqrt(3/5)`