How do you find the zeros, real and imaginary, of y=2x29x+5 using the quadratic formula?

1 Answer
Apr 22, 2018

Zeros are real and x=0.5,x=5

Explanation:

y=2x29x+5

Comparing with standard quadratic equation ax2+bx+c=0

a=2,b=9,c=5. Discriminant D=b24ac or

D=81+40=121 , discriminant is positive, we get two real

solutions. Quadratic formula: x=b±D2aor

x=9±1214=9±114x=204=5 or

x=24=0.5 Zeros are real and x=0.5,x=5 [Ans]