How do you find the zeros, real and imaginary, of #y=3x^2+17x-3# using the quadratic formula?
The quadratic has 2 real roots at
To begin, we must put our quadratic in the standard form (which is it already) and set
The quadratic formula uses the form:
where a,b, and c can be gotten from the equation above. The roots are given by:
If the roots are complex, we will get a negative number under the square root. In our case the roots are given by: