# How do you find the zeros, real and imaginary, of y=5x^2+7x+12 using the quadratic formula?

Jun 5, 2016

$x = - \frac{7}{10} \pm \frac{\sqrt{191}}{10} i$

#### Explanation:

let's solve the equation
$5 {x}^{2} + 7 x + 12 = 0$
using the quadratic formula, so
$x = \frac{- 7 \pm \sqrt{49 - 240}}{10}$
under root we have a negative number, so the solutions are not real
$x = - \frac{7}{10} - \frac{\sqrt{191}}{10} i$
and
$x = - \frac{7}{10} + \frac{\sqrt{191}}{10} i$