# How do you find the zeros, real and imaginary, of y=5x^2-x-2 using the quadratic formula?

Jan 11, 2016

The zeroes are given by y=$\frac{1 \left(\frac{+}{-}\right) \sqrt{41}}{10}$
The quadratic equation, which gives the roots of a second degree polynomial of the form $a {x}^{2} + b x + c$, is:
$\frac{- b \left(\frac{+}{-}\right) \sqrt{{b}^{2} - 4 a c}}{2 a}$.
Substituting for a the value 5, for b the value -1, and for c the value -2, gives $\frac{- \left(- 1\right) \left(\frac{+}{-}\right) \sqrt{{\left(- 1\right)}^{2} - 4 \left(5\right) \left(- 2\right)}}{2 \left(5\right)}$. This gives the stated values.