Question

How do you find the zeros, real and imaginary, of `y= 8x^2+3x-24` using the quadratic formula?

Answer 1

`x=(-3+-sqrt777)/16`

Explanation:

The quadratic formula states that for a quadratic equation `ax^2+bx+c`, `color(red)(x=(-b+-sqrt(b^2-4ac))/(2a)`.

We know from your equation that: `a=8,b=3,c=-24`

`x=(-3+-sqrt(3^2-4(8)(-24)))/(2(8))=(-3+-sqrt777)/16`

`777` is prime. These are your fully simplified answers, which are irrational but real.