# How do you find the zeros, real and imaginary, of y= 8x^2+3x-24 using the quadratic formula?

Nov 21, 2015

$x = \frac{- 3 \pm \sqrt{777}}{16}$

#### Explanation:

The quadratic formula states that for a quadratic equation $a {x}^{2} + b x + c$, color(red)(x=(-b+-sqrt(b^2-4ac))/(2a).

We know from your equation that: $a = 8 , b = 3 , c = - 24$

$x = \frac{- 3 \pm \sqrt{{3}^{2} - 4 \left(8\right) \left(- 24\right)}}{2 \left(8\right)} = \frac{- 3 \pm \sqrt{777}}{16}$

$777$ is prime. These are your fully simplified answers, which are irrational but real.