Question

How do you find the zeros, real and imaginary, of `y=-x^2-2x+33` using the quadratic formula?

Answer 1

Two real roots:
`- 1 +- sqrt34`

Explanation:

Use the improved quadratic formula (Socratic Search)
`y= -x^2 - 2x + 33 = 0`
`D = d^2 = b^2 - 4ac = 4 + 132 = 136` --> `d = +- 2sqrt34`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = 2/-2 +- (2sqrt34)/-2 = -1 +- sqrt34`