How do you find the zeros, real and imaginary, of #y=-x^2+7x+12# using the quadratic formula?

1 Answer
May 15, 2017

Answer:

#x=7/2+sqrt97/2#
or
#x=7/2-sqrt97/2#

Explanation:

Let my awesome notebook explain :D
(I can't be bothered with all the symbols on Socratic so I'll just do it on paper and then take a photo)

The roots, or the zeros of this question is real because the discriminant is positive. The discriminant is the #sqrtb^2-4ac# part.

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