# How do you find the zeros, real and imaginary, of y=-x^2+7x+12 using the quadratic formula?

May 15, 2017

$x = \frac{7}{2} + \frac{\sqrt{97}}{2}$
$x = \frac{7}{2} - \frac{\sqrt{97}}{2}$
The roots, or the zeros of this question is real because the discriminant is positive. The discriminant is the ${\sqrt{b}}^{2} - 4 a c$ part.