How do you find three consecutive multiples of 3 if twice the second is 12?
Good question! Here is my explanation:
Since twice the second is 12, the second number should be 6 since half of 12 is 6. If you want 3 consecutive multiples of 3, you can put this:
It's as easy as that! Good luck! Feel free to ask me questions. (my explanations aren't the best)