How do you find three consecutive odd integers such that he sum of the first and twice the second is 6 more than the third?
See process for finding the solution to this problem below:
First, let's define the three consecutive odd numbers.
The first, we can call
Because they are odd numbers we know they are every other number from
The second and third number will be
"twice the second" is the same as:
"the sum of the first and twice the second is then:
This sum is "6 more than the third" or
Putting this into an equation and solving for
The first number is 3 and therefore the next two consecutive odd numbers are 5 and 7