Question

How do you find two consecutive even integers that have 452 as the sum of their squares?

Answer 1

`-16, 14`

Explanation:

Two consecutive even integers can be represented as

`2n, 2n+2` so the condition is

`(2n)^2+(2n+2)^2=452`. Solving for `n` we have

`n = -8` and `n = 7` so the numbers are

`-16` and `14`