# How do you find two consecutive integers whose sum is 211?

Jul 22, 2017

$105 \text{ and } 106$

#### Explanation:

$\text{integers are 1 unit apart}$

$\text{let n be an integer then a consecutive integer is n + 1}$

$\Rightarrow n + \left(n + 1\right) = 211 \leftarrow \text{ solve for n}$

$\Rightarrow 2 n + 1 = 211$

$\text{subtract 1 from both sides}$

$2 n \cancel{+ 1} \cancel{- 1} = 211 - 1$

$\Rightarrow 2 n = 210$

$\text{divide both sides by 2}$

$\frac{\cancel{2} n}{\cancel{2}} = \frac{210}{2}$

$\Rightarrow n = 105 \text{ and } n + 1 = 105 + 1 = 106$

$\text{thus the 2 consecutive integers are " 105" and } 106$