How do you find two consecutive odd integers whose product is 1 less than 6 times their sum?
There are two sets of consecutive odd integers which meet the requirements of this problem:
11 and 13
-1 and 1
First, let's define our numbers in mathematical terms.
So this problem can now be rewritten as:
Next create a quadratic equation:
Factoring this gives:
Solving first for
Solving for (x + 1) gives: