# How do you find two consecutive odd integers whose product is 1 less than 6 times their sum?

##### 1 Answer

There are two sets of consecutive odd integers which meet the requirements of this problem:

11 and 13

or

-1 and 1

#### Explanation:

First, let's define our numbers in mathematical terms.

Let

So this problem can now be rewritten as:

Next create a quadratic equation:

Factoring this gives:

Solving first for

Solving for (x + 1) gives: