# How do you find vertical, horizontal and oblique asymptotes for # (2x+sqrt(4-x^2)) / (3x^2-x-2)#?

##### 1 Answer

Dec 16, 2016

Horizontal:

#### Explanation:

To make y real,

The equation is

So,

As x is bounded, there is no horizontal asymptote, and for the same

reason, there is no slant asymptote.

The illustrative graph is inserted.

graph{y(x-1)(3x+2)-2x-sqrt(4-x^2)=0 [-10, 10, -5, 5]}