# How do you find vertical, horizontal and oblique asymptotes for # f(x)= (3x^2 + 15x +18 )/( 4x^2-4)#?

##### 1 Answer

Dec 4, 2016

Vertical:

Horizontal:

Illustrative graph is inserted.

#### Explanation:

Zeros: x = 0 and 4.

AS

As

Interestingly, the asymptote y = 3/4 cuts the graph#

at

Yet, it is tangent at infinity.

graph{y(4x^2-4)-(3x^2+15x+18)=0 [-24.43, 24.43, -12.22, 12.22]}