# How do you find vertical, horizontal and oblique asymptotes for x/(1-x)^2?

Jun 13, 2017

$y = 0$

$x = 1$

#### Explanation:

The degree of the bottom is 2, and the degree of the top is 1. Therefore, there will be a horizontal asymptote at $y = 0$ since the function will tend towards 0 as x goes to $\infty$. This also means there will be no oblique asymptote.

As far as vertical asymptotes, they will occur when the denominator is 0 and the numerator is non-zero. For this function, this will happen when $x = 1$ since this makes the bottom equal to 0 and the top equal to 1.

So our asymptotes are $y = 0$ and $x = 1$